2=-3(3p+4)+8(1+p)

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Solution for 2=-3(3p+4)+8(1+p) equation: 



2=-3(3p+4)+8(1+p)

We move all terms to the left:

2-(-3(3p+4)+8(1+p))=0

We add all the numbers together, and all the variables

-(-3(3p+4)+8(p+1))+2=0



We calculate terms in parentheses: -(-3(3p+4)+8(p+1)), so:

-3(3p+4)+8(p+1)

We multiply parentheses

-9p+8p-12+8

We add all the numbers together, and all the variables

-1p-4

Back to the equation:

-(-1p-4)



We get rid of parentheses

1p+4+2=0

We add all the numbers together, and all the variables

p+6=0

We move all terms containing p to the left, all other terms to the right

p=-6

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