2=-5/3c+9

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Solution for 2=-5/3c+9 equation: 



2=-5/3c+9

We move all terms to the left:

2-(-5/3c+9)=0



Domain of the equation: 3c+9)!=0

c∈R



We get rid of parentheses

5/3c-9+2=0

We multiply all the terms by the denominator


-9*3c+2*3c+5=0

Wy multiply elements

-27c+6c+5=0

We add all the numbers together, and all the variables

-21c+5=0

We move all terms containing c to the left, all other terms to the right

-21c=-5

c=-5/-21

c=5/21

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