2=-5y+2(y-2)

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Solution for 2=-5y+2(y-2) equation: 



2=-5y+2(y-2)

We move all terms to the left:

2-(-5y+2(y-2))=0



We calculate terms in parentheses: -(-5y+2(y-2)), so:

-5y+2(y-2)

We multiply parentheses

-5y+2y-4

We add all the numbers together, and all the variables

-3y-4

Back to the equation:

-(-3y-4)



We get rid of parentheses

3y+4+2=0

We add all the numbers together, and all the variables

3y+6=0

We move all terms containing y to the left, all other terms to the right

3y=-6

y=-6/3

y=-2

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