2=-8(1+2b)+2(3b-5)

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Solution for 2=-8(1+2b)+2(3b-5) equation: 



2=-8(1+2b)+2(3b-5)

We move all terms to the left:

2-(-8(1+2b)+2(3b-5))=0

We add all the numbers together, and all the variables

-(-8(2b+1)+2(3b-5))+2=0



We calculate terms in parentheses: -(-8(2b+1)+2(3b-5)), so:

-8(2b+1)+2(3b-5)

We multiply parentheses

-16b+6b-8-10

We add all the numbers together, and all the variables

-10b-18

Back to the equation:

-(-10b-18)



We get rid of parentheses

10b+18+2=0

We add all the numbers together, and all the variables

10b+20=0

We move all terms containing b to the left, all other terms to the right

10b=-20

b=-20/10

b=-2

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