2=1+2/(z+2)

Solution for 2=1+2/(z+2) equation:

2=1+2/(z+2)

We move all terms to the left:

2-(1+2/(z+2))=0


Domain of the equation: (z+2))!=0

z∈R


We multiply all the terms by the denominator


-(1+2+2*(z+2))=0


We calculate terms in parentheses: -(1+2+2*(z+2)), so:

1+2+2*(z+2)

determiningTheFunctionDomain
2*(z+2)+1+2

We add all the numbers together, and all the variables

2*(z+2)+3

We multiply parentheses

2z+4+3

We add all the numbers together, and all the variables

2z+7

Back to the equation:

-(2z+7)


We get rid of parentheses

-2z-7=0

We move all terms containing z to the left, all other terms to the right

-2z=7

z=7/-2

z=-3+1/2