2=1/2(9z-2)

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Solution for 2=1/2(9z-2) equation: 



2=1/2(9z-2)

We move all terms to the left:

2-(1/2(9z-2))=0



Domain of the equation: 2(9z-2))!=0

z∈R



We multiply all the terms by the denominator


-(1+2*2(9z-2))=0



We calculate terms in parentheses: -(1+2*2(9z-2)), so:

1+2*2(9z-2)

determiningTheFunctionDomain
2*2(9z-2)+1

Wy multiply elements

4z(9+1

Back to the equation:

-(4z(9+1)



We add all the numbers together, and all the variables

-(4z10=0

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