2=1/3(3)+b

Solution for 2=1/3(3)+b equation:

2=1/3(3)+b

We move all terms to the left:

2-(1/3(3)+b)=0


Domain of the equation: 33+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-33

b!=-33/1

b!=-33

b∈R


We add all the numbers together, and all the variables

-(+b+1/33)+2=0

We get rid of parentheses

-b+2-1/33=0

We multiply all the terms by the denominator


-b*33-1+2*33=0

We add all the numbers together, and all the variables

-b*33+65=0

Wy multiply elements

-33b+65=0

We move all terms containing b to the left, all other terms to the right

-33b=-65

b=-65/-33

b=1+32/33