2=1/3(k+1)

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Solution for 2=1/3(k+1) equation: 



2=1/3(k+1)

We move all terms to the left:

2-(1/3(k+1))=0



Domain of the equation: 3(k+1))!=0

k∈R



We multiply all the terms by the denominator


-(1+2*3(k+1))=0



We calculate terms in parentheses: -(1+2*3(k+1)), so:

1+2*3(k+1)

determiningTheFunctionDomain
2*3(k+1)+1

Wy multiply elements

6k(k+1

Back to the equation:

-(6k(k+1)





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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6k(k+1





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