2=1/5(-8)+b

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Solution for 2=1/5(-8)+b equation: 



2=1/5(-8)+b

We move all terms to the left:

2-(1/5(-8)+b)=0



Domain of the equation: 5(-8)+b)!=0

b∈R



We multiply all the terms by the denominator


-(1+2*5(-8)+b)=0



We calculate terms in parentheses: -(1+2*5(-8)+b), so:

1+2*5(-8)+b

determiningTheFunctionDomain
b+1+2*5(-8)

We add all the numbers together, and all the variables

b-79

Back to the equation:

-(b-79)



We get rid of parentheses

-b+79=0

We add all the numbers together, and all the variables

-1b+79=0

We move all terms containing b to the left, all other terms to the right

-b=-79

b=-79/-1

b=+79

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