2=11+3m(m+3)

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Solution for 2=11+3m(m+3) equation: 



2=11+3m(m+3)

We move all terms to the left:

2-(11+3m(m+3))=0



We calculate terms in parentheses: -(11+3m(m+3)), so:

11+3m(m+3)

determiningTheFunctionDomain
3m(m+3)+11

We multiply parentheses

3m^2+9m+11

Back to the equation:

-(3m^2+9m+11)



We get rid of parentheses

-3m^2-9m-11+2=0

We add all the numbers together, and all the variables

-3m^2-9m-9=0

a = -3; b = -9; c = -9;
Δ = b2-4ac
Δ = -92-4·(-3)·(-9)
Δ = -27
Delta is less than zero, so there is no solution for the equation

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