2=2(10-4y)/(3)-2y

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Solution for 2=2(10-4y)/(3)-2y equation: 



2=2(10-4y)/(3)-2y

We move all terms to the left:

2-(2(10-4y)/(3)-2y)=0



Domain of the equation: 3-2y)!=0

We move all terms containing y to the left, all other terms to the right

-2y)!=-3

y!=-3/1

y!=-3

y∈R



We add all the numbers together, and all the variables

-(2(-4y+10)/3-2y)+2=0

We multiply all the terms by the denominator


-(2(-4y+10)+2*3-2y)=0



We calculate terms in parentheses: -(2(-4y+10)+2*3-2y), so:

2(-4y+10)+2*3-2y

determiningTheFunctionDomain
2(-4y+10)-2y+2*3

We add all the numbers together, and all the variables

-2y+2(-4y+10)+6

We multiply parentheses

-2y-8y+20+6

We add all the numbers together, and all the variables

-10y+26

Back to the equation:

-(-10y+26)



We get rid of parentheses

10y-26=0

We move all terms containing y to the left, all other terms to the right

10y=26

y=26/10

y=2+3/5

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