2=2(j+-6)+10

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Solution for 2=2(j+-6)+10 equation: 



2=2(j+-6)+10

We move all terms to the left:

2-(2(j+-6)+10)=0

We add all the numbers together, and all the variables

-(2(j-6)+10)+2=0



We calculate terms in parentheses: -(2(j-6)+10), so:

2(j-6)+10

We multiply parentheses

2j-12+10

We add all the numbers together, and all the variables

2j-2

Back to the equation:

-(2j-2)



We get rid of parentheses

-2j+2+2=0

We add all the numbers together, and all the variables

-2j+4=0

We move all terms containing j to the left, all other terms to the right

-2j=-4

j=-4/-2

j=+2

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