2=2/(y+2)

Solution for 2=2/(y+2) equation:

2=2/(y+2)

We move all terms to the left:

2-(2/(y+2))=0


Domain of the equation: (y+2))!=0

y∈R


We multiply all the terms by the denominator


-(2+2*(y+2))=0


We calculate terms in parentheses: -(2+2*(y+2)), so:

2+2*(y+2)

determiningTheFunctionDomain
2*(y+2)+2

We multiply parentheses

2y+4+2

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)


We get rid of parentheses

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3