2=2/3(3)+b

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Solution for 2=2/3(3)+b equation: 



2=2/3(3)+b

We move all terms to the left:

2-(2/3(3)+b)=0



Domain of the equation: 33+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-33

b!=-33/1

b!=-33

b∈R



We add all the numbers together, and all the variables

-(+b+2/33)+2=0

We get rid of parentheses

-b+2-2/33=0

We multiply all the terms by the denominator


-b*33-2+2*33=0

We add all the numbers together, and all the variables

-b*33+64=0

Wy multiply elements

-33b+64=0

We move all terms containing b to the left, all other terms to the right

-33b=-64

b=-64/-33

b=1+31/33

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