2=2y-(2y-2)

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Solution for 2=2y-(2y-2) equation: 



2=2y-(2y-2)

We move all terms to the left:

2-(2y-(2y-2))=0



We calculate terms in parentheses: -(2y-(2y-2)), so:

2y-(2y-2)

We get rid of parentheses

2y-2y+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

=0

y=0/1

y=0

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