2=3(3x-6)=5(x-3)+15

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Solution for 2=3(3x-6)=5(x-3)+15 equation: 



2=3(3x-6)=5(x-3)+15

We move all terms to the left:

2-(3(3x-6))=0



We calculate terms in parentheses: -(3(3x-6)), so:

3(3x-6)

We multiply parentheses

9x-18

Back to the equation:

-(9x-18)



We get rid of parentheses

-9x+18+2=0

We add all the numbers together, and all the variables

-9x+20=0

We move all terms containing x to the left, all other terms to the right

-9x=-20

x=-20/-9

x=2+2/9

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