2=3(x-4)-(x-8)

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Solution for 2=3(x-4)-(x-8) equation: 



2=3(x-4)-(x-8)

We move all terms to the left:

2-(3(x-4)-(x-8))=0



We calculate terms in parentheses: -(3(x-4)-(x-8)), so:

3(x-4)-(x-8)

We multiply parentheses

3x-(x-8)-12

We get rid of parentheses

3x-x+8-12

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

-2x+4+2=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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