2=3+x-2/x-4

Solution for 2=3+x-2/x-4 equation:

2=3+x-2/x-4

We move all terms to the left:

2-(3+x-2/x-4)=0


Domain of the equation: x-4)!=0

x∈R


We add all the numbers together, and all the variables

-(x-2/x-1)+2=0

We get rid of parentheses

-x+2/x+1+2=0

We multiply all the terms by the denominator


-x*x+1*x+2*x+2=0

We add all the numbers together, and all the variables

3x-x*x+2=0

Wy multiply elements

-1x^2+3x+2=0

a = -1; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-1)·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*-1}=\frac{-3-\sqrt{17}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*-1}=\frac{-3+\sqrt{17}}{-2}
$