2=4(z-3)-2z

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Solution for 2=4(z-3)-2z equation:



2=4(z-3)-2z
We move all terms to the left:
2-(4(z-3)-2z)=0
We calculate terms in parentheses: -(4(z-3)-2z), so:
4(z-3)-2z
We add all the numbers together, and all the variables
-2z+4(z-3)
We multiply parentheses
-2z+4z-12
We add all the numbers together, and all the variables
2z-12
Back to the equation:
-(2z-12)
We get rid of parentheses
-2z+12+2=0
We add all the numbers together, and all the variables
-2z+14=0
We move all terms containing z to the left, all other terms to the right
-2z=-14
z=-14/-2
z=+7

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