2=5(7f+4)+3

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Solution for 2=5(7f+4)+3 equation: 



2=5(7f+4)+3

We move all terms to the left:

2-(5(7f+4)+3)=0



We calculate terms in parentheses: -(5(7f+4)+3), so:

5(7f+4)+3

We multiply parentheses

35f+20+3

We add all the numbers together, and all the variables

35f+23

Back to the equation:

-(35f+23)



We get rid of parentheses

-35f-23+2=0

We add all the numbers together, and all the variables

-35f-21=0

We move all terms containing f to the left, all other terms to the right

-35f=21

f=21/-35

f=-3/5

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