2=5(7f+4)+3

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Solution for 2=5(7f+4)+3 equation:



2=5(7f+4)+3
We move all terms to the left:
2-(5(7f+4)+3)=0
We calculate terms in parentheses: -(5(7f+4)+3), so:
5(7f+4)+3
We multiply parentheses
35f+20+3
We add all the numbers together, and all the variables
35f+23
Back to the equation:
-(35f+23)
We get rid of parentheses
-35f-23+2=0
We add all the numbers together, and all the variables
-35f-21=0
We move all terms containing f to the left, all other terms to the right
-35f=21
f=21/-35
f=-3/5

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