2=5/2b+2b/b+1

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Solution for 2=5/2b+2b/b+1 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

2 = (5/2)*b+(2*b)/b+1 // - (5/2)*b+(2*b)/b+1

2-((5/2)*b)-((2*b)/b)-1 = 0

(-5/2)*b-2-1+2 = 0

-5/2*b-1 = 0 // + 1

-5/2*b = 1 // : -5/2

b = 1/(-5/2)

b = -2/5

b = -2/5

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