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2=5/9(f-32
We move all terms to the left:
2-(5/9(f-32)=0
Domain of the equation: 9(f-32)+2!=0We multiply all the terms by the denominator
We move all terms containing f to the left, all other terms to the right
9(f-32)!=-2
f∈R
-(5=0
We add all the numbers together, and all the variables
=0
f=0/1
f=0
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