2=7(c+4)+9c

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Solution for 2=7(c+4)+9c equation:



2=7(c+4)+9c
We move all terms to the left:
2-(7(c+4)+9c)=0
We calculate terms in parentheses: -(7(c+4)+9c), so:
7(c+4)+9c
We add all the numbers together, and all the variables
9c+7(c+4)
We multiply parentheses
9c+7c+28
We add all the numbers together, and all the variables
16c+28
Back to the equation:
-(16c+28)
We get rid of parentheses
-16c-28+2=0
We add all the numbers together, and all the variables
-16c-26=0
We move all terms containing c to the left, all other terms to the right
-16c=26
c=26/-16
c=-1+5/8

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