2=7(c+4)+9c

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Solution for 2=7(c+4)+9c equation: 



2=7(c+4)+9c

We move all terms to the left:

2-(7(c+4)+9c)=0



We calculate terms in parentheses: -(7(c+4)+9c), so:

7(c+4)+9c

We add all the numbers together, and all the variables

9c+7(c+4)

We multiply parentheses

9c+7c+28

We add all the numbers together, and all the variables

16c+28

Back to the equation:

-(16c+28)



We get rid of parentheses

-16c-28+2=0

We add all the numbers together, and all the variables

-16c-26=0

We move all terms containing c to the left, all other terms to the right

-16c=26

c=26/-16

c=-1+5/8

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