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2=7x+4x^2
We move all terms to the left:
2-(7x+4x^2)=0
We get rid of parentheses
-4x^2-7x+2=0
a = -4; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·(-4)·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*-4}=\frac{-2}{-8} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*-4}=\frac{16}{-8} =-2 $
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