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2=8-(4/3h)
We move all terms to the left:
2-(8-(4/3h))=0
Domain of the equation: 3h))!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(8-(+4/3h))+2=0
We multiply all the terms by the denominator
-(8-(+4+2*3h))=0
We calculate terms in parentheses: -(8-(+4+2*3h)), so:We get rid of parentheses
8-(+4+2*3h)
determiningTheFunctionDomain -(+4+2*3h)+8
We add all the numbers together, and all the variables
-(2*3h+4)+8
We get rid of parentheses
-2*3h-4+8
We add all the numbers together, and all the variables
-2*3h+4
Wy multiply elements
-6h+4
Back to the equation:
-(-6h+4)
6h-4=0
We move all terms containing h to the left, all other terms to the right
6h=4
h=4/6
h=2/3
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