2=8y+6(y-3)

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Solution for 2=8y+6(y-3) equation: 



2=8y+6(y-3)

We move all terms to the left:

2-(8y+6(y-3))=0



We calculate terms in parentheses: -(8y+6(y-3)), so:

8y+6(y-3)

We multiply parentheses

8y+6y-18

We add all the numbers together, and all the variables

14y-18

Back to the equation:

-(14y-18)



We get rid of parentheses

-14y+18+2=0

We add all the numbers together, and all the variables

-14y+20=0

We move all terms containing y to the left, all other terms to the right

-14y=-20

y=-20/-14

y=1+3/7

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