2=log(d+1)

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Solution for 2=log(d+1) equation:


Simplifying
2 = log(d + 1)

Reorder the terms:
2 = glo(1 + d)
2 = (1 * glo + d * glo)

Reorder the terms:
2 = (dglo + 1glo)
2 = (dglo + 1glo)

Solving
2 = dglo + 1glo

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1dglo' to each side of the equation.
2 + -1dglo = dglo + -1dglo + 1glo

Combine like terms: dglo + -1dglo = 0
2 + -1dglo = 0 + 1glo
2 + -1dglo = 1glo

Add '-2' to each side of the equation.
2 + -2 + -1dglo = -2 + 1glo

Combine like terms: 2 + -2 = 0
0 + -1dglo = -2 + 1glo
-1dglo = -2 + 1glo

Divide each side by '-1glo'.
d = 2g-1l-1o-1 + -1

Simplifying
d = 2g-1l-1o-1 + -1

Reorder the terms:
d = -1 + 2g-1l-1o-1

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