2=u-35/u

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Solution for 2=u-35/u equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

2 = u-(35/u) // - u-(35/u)

35/u-u+2 = 0

35*u^-1-1*u^1+2*u^0 = 0

(2*u^1-1*u^2+35*u^0)/(u^1) = 0 // * u^2

u^1*(2*u^1-1*u^2+35*u^0) = 0

u^1

2*u-u^2+35 = 0

2*u-u^2+35 = 0

DELTA = 2^2-(-1*4*35)

DELTA = 144

DELTA > 0

u = (144^(1/2)-2)/(-1*2) or u = (-144^(1/2)-2)/(-1*2)

u = -5 or u = 7

u in { -5, 7} 

u in { -5, 7 }

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