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2=x(1+6x)
We move all terms to the left:
2-(x(1+6x))=0
We add all the numbers together, and all the variables
-(x(6x+1))+2=0
We calculate terms in parentheses: -(x(6x+1)), so:We get rid of parentheses
x(6x+1)
We multiply parentheses
6x^2+x
Back to the equation:
-(6x^2+x)
-6x^2-x+2=0
We add all the numbers together, and all the variables
-6x^2-1x+2=0
a = -6; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·(-6)·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*-6}=\frac{-6}{-12} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*-6}=\frac{8}{-12} =-2/3 $
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