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2=x(3-1)(3-5)
We move all terms to the left:
2-(x(3-1)(3-5))=0
We add all the numbers together, and all the variables
-(x2(-2))+2=0
We calculate terms in parentheses: -(x2(-2)), so:We get rid of parentheses
x2(-2)
We multiply parentheses
-2x^2
Back to the equation:
-(-2x^2)
2x^2+2=0
a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation
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