2=y2-4/2

Solution for 2=y2-4/2 equation:

2=y2-4/2

We move all terms to the left:

2-(y2-4/2)=0

We add all the numbers together, and all the variables

-(+y^2-4/2)+2=0

We get rid of parentheses

-y^2+2+4/2=0

We multiply all the terms by the denominator


-y^2*2+4+2*2=0

We add all the numbers together, and all the variables

-y^2*2+8=0

Wy multiply elements

-2y^2+8=0

a = -2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-2)·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-2}=\frac{-8}{-4}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-2}=\frac{8}{-4}
=-2
$