2B-5=2+3(x+3)

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Solution for 2B-5=2+3(x+3) equation: 



2-5=2+3(B+3)

We move all terms to the left:

2-5-(2+3(B+3))=0

We add all the numbers together, and all the variables

-(2+3(B+3))-3=0



We calculate terms in parentheses: -(2+3(B+3)), so:

2+3(B+3)

determiningTheFunctionDomain
3(B+3)+2

We multiply parentheses

3B+9+2

We add all the numbers together, and all the variables

3B+11

Back to the equation:

-(3B+11)



We get rid of parentheses

-3B-11-3=0

We add all the numbers together, and all the variables

-3B-14=0

We move all terms containing B to the left, all other terms to the right

-3B=14

B=14/-3

B=-4+2/3

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