2a(-8a+3)=0

Solution for 2a(-8a+3)=0 equation:

2a(-8a+3)=0

We multiply parentheses

-16a^2+6a=0

a = -16; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-16)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-16}=\frac{-12}{-32}
=3/8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-16}=\frac{0}{-32}
=0
$