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2a(3+5a)=22
We move all terms to the left:
2a(3+5a)-(22)=0
We add all the numbers together, and all the variables
2a(5a+3)-22=0
We multiply parentheses
10a^2+6a-22=0
a = 10; b = 6; c = -22;
Δ = b2-4ac
Δ = 62-4·10·(-22)
Δ = 916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{916}=\sqrt{4*229}=\sqrt{4}*\sqrt{229}=2\sqrt{229}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{229}}{2*10}=\frac{-6-2\sqrt{229}}{20} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{229}}{2*10}=\frac{-6+2\sqrt{229}}{20} $
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