2a(3-4a)=10-a(8a)

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Solution for 2a(3-4a)=10-a(8a) equation: 



2a(3-4a)=10-a(8a)

We move all terms to the left:

2a(3-4a)-(10-a(8a))=0

We add all the numbers together, and all the variables

2a(-4a+3)-(-a8a+10)=0

We multiply parentheses

-8a^2+6a-(-a8a+10)=0

We get rid of parentheses

-8a^2+6a+a8a-10=0

We move all terms containing a to the left, all other terms to the right

-8a^2+6a+a8a=10

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