2a(4-3a)=0

Solution for 2a(4-3a)=0 equation:

2a(4-3a)=0

We add all the numbers together, and all the variables

2a(-3a+4)=0

We multiply parentheses

-6a^2+8a=0

a = -6; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-6)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-6}=\frac{-16}{-12}
=1+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-6}=\frac{0}{-12}
=0
$