2a(a+3)-a*a=3a(2-a)

Solution for 2a(a+3)-a*a=3a(2-a) equation:

2a(a+3)-a*a=3a(2-a)

We move all terms to the left:

2a(a+3)-a*a-(3a(2-a))=0

We add all the numbers together, and all the variables

2a(a+3)-a*a-(3a(-1a+2))=0

We multiply parentheses

2a^2+6a-a*a-(3a(-1a+2))=0

Wy multiply elements

2a^2-1a^2+6a-(3a(-1a+2))=0


We calculate terms in parentheses: -(3a(-1a+2)), so:

3a(-1a+2)

We multiply parentheses

-3a^2+6a

Back to the equation:

-(-3a^2+6a)


We add all the numbers together, and all the variables

a^2-(-3a^2+6a)+6a=0

We get rid of parentheses

a^2+3a^2-6a+6a=0

We add all the numbers together, and all the variables

4a^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{8}=0$