2a+3(a+5)=-4a-(3a-1)+6

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Solution for 2a+3(a+5)=-4a-(3a-1)+6 equation: 



2a+3(a+5)=-4a-(3a-1)+6

We move all terms to the left:

2a+3(a+5)-(-4a-(3a-1)+6)=0

We multiply parentheses

2a+3a-(-4a-(3a-1)+6)+15=0



We calculate terms in parentheses: -(-4a-(3a-1)+6), so:

-4a-(3a-1)+6

We get rid of parentheses

-4a-3a+1+6

We add all the numbers together, and all the variables

-7a+7

Back to the equation:

-(-7a+7)



We add all the numbers together, and all the variables

5a-(-7a+7)+15=0

We get rid of parentheses

5a+7a-7+15=0

We add all the numbers together, and all the variables

12a+8=0

We move all terms containing a to the left, all other terms to the right

12a=-8

a=-8/12

a=-2/3

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