2a+3=(1)/(2)(6+4a)

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Solution for 2a+3=(1)/(2)(6+4a) equation: 


a in (-oo:+oo)

2*a+3 = (1/2)*(4*a+6) // - (1/2)*(4*a+6)

2*a-((1/2)*(4*a+6))+3 = 0

(-1/2)*(4*a+6)+2*a+3 = 0

2*a-1/2*(4*a+6)+3 = 0

2*a-1/2*(4*a+6)+3 = 0

3-3 = 0

0 = 0

0 = 0

a belongs to the empty set

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