2a+3b+2c=68

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Solution for 2a+3b+2c=68 equation:


Simplifying
2a + 3b + 2c = 68

Solving
2a + 3b + 2c = 68

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3b' to each side of the equation.
2a + 3b + -3b + 2c = 68 + -3b

Combine like terms: 3b + -3b = 0
2a + 0 + 2c = 68 + -3b
2a + 2c = 68 + -3b

Add '-2c' to each side of the equation.
2a + 2c + -2c = 68 + -3b + -2c

Combine like terms: 2c + -2c = 0
2a + 0 = 68 + -3b + -2c
2a = 68 + -3b + -2c

Divide each side by '2'.
a = 34 + -1.5b + -1c

Simplifying
a = 34 + -1.5b + -1c

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