2a+4(a-4)=32

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Solution for 2a+4(a-4)=32 equation: 



2a+4(a-4)=32

We move all terms to the left:

2a+4(a-4)-(32)=0

We multiply parentheses

2a+4a-16-32=0

We add all the numbers together, and all the variables

6a-48=0

We move all terms containing a to the left, all other terms to the right

6a=48

a=48/6

a=8

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