2a+5-3a-2=2(a+1)-5a-2+10

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Solution for 2a+5-3a-2=2(a+1)-5a-2+10 equation: 



2a+5-3a-2=2(a+1)-5a-2+10

We move all terms to the left:

2a+5-3a-2-(2(a+1)-5a-2+10)=0

We add all the numbers together, and all the variables

-1a-(2(a+1)-5a-2+10)+3=0



We calculate terms in parentheses: -(2(a+1)-5a-2+10), so:

2(a+1)-5a-2+10

We add all the numbers together, and all the variables

-5a+2(a+1)+8

We multiply parentheses

-5a+2a+2+8

We add all the numbers together, and all the variables

-3a+10

Back to the equation:

-(-3a+10)



We get rid of parentheses

-1a+3a-10+3=0

We add all the numbers together, and all the variables

2a-7=0

We move all terms containing a to the left, all other terms to the right

2a=7

a=7/2

a=3+1/2

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