2a-(3a-1)=4-(2a+5)

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Solution for 2a-(3a-1)=4-(2a+5) equation: 



2a-(3a-1)=4-(2a+5)

We move all terms to the left:

2a-(3a-1)-(4-(2a+5))=0

We get rid of parentheses

2a-3a-(4-(2a+5))+1=0



We calculate terms in parentheses: -(4-(2a+5)), so:

4-(2a+5)

determiningTheFunctionDomain
-(2a+5)+4

We get rid of parentheses

-2a-5+4

We add all the numbers together, and all the variables

-2a-1

Back to the equation:

-(-2a-1)



We add all the numbers together, and all the variables

-1a-(-2a-1)+1=0

We get rid of parentheses

-1a+2a+1+1=0

We add all the numbers together, and all the variables

a+2=0

We move all terms containing a to the left, all other terms to the right

a=-2

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