2a-10=4(a+1)+16a+5

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Solution for 2a-10=4(a+1)+16a+5 equation: 



2a-10=4(a+1)+16a+5

We move all terms to the left:

2a-10-(4(a+1)+16a+5)=0



We calculate terms in parentheses: -(4(a+1)+16a+5), so:

4(a+1)+16a+5

We add all the numbers together, and all the variables

16a+4(a+1)+5

We multiply parentheses

16a+4a+4+5

We add all the numbers together, and all the variables

20a+9

Back to the equation:

-(20a+9)



We get rid of parentheses

2a-20a-9-10=0

We add all the numbers together, and all the variables

-18a-19=0

We move all terms containing a to the left, all other terms to the right

-18a=19

a=19/-18

a=-1+1/18

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