2a-1=(a+1)+7a+5

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Solution for 2a-1=(a+1)+7a+5 equation: 



2a-1=(a+1)+7a+5

We move all terms to the left:

2a-1-((a+1)+7a+5)=0



We calculate terms in parentheses: -((a+1)+7a+5), so:

(a+1)+7a+5

We add all the numbers together, and all the variables

7a+(a+1)+5

We get rid of parentheses

7a+a+1+5

We add all the numbers together, and all the variables

8a+6

Back to the equation:

-(8a+6)



We get rid of parentheses

2a-8a-6-1=0

We add all the numbers together, and all the variables

-6a-7=0

We move all terms containing a to the left, all other terms to the right

-6a=7

a=7/-6

a=-1+1/6

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