2a-4(6-4a)=13a-5-(a+3)

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Solution for 2a-4(6-4a)=13a-5-(a+3) equation: 



2a-4(6-4a)=13a-5-(a+3)

We move all terms to the left:

2a-4(6-4a)-(13a-5-(a+3))=0

We add all the numbers together, and all the variables

2a-4(-4a+6)-(13a-5-(a+3))=0

We multiply parentheses

2a+16a-(13a-5-(a+3))-24=0



We calculate terms in parentheses: -(13a-5-(a+3)), so:

13a-5-(a+3)

determiningTheFunctionDomain
13a-(a+3)-5

We get rid of parentheses

13a-a-3-5

We add all the numbers together, and all the variables

12a-8

Back to the equation:

-(12a-8)



We add all the numbers together, and all the variables

18a-(12a-8)-24=0

We get rid of parentheses

18a-12a+8-24=0

We add all the numbers together, and all the variables

6a-16=0

We move all terms containing a to the left, all other terms to the right

6a=16

a=16/6

a=2+2/3

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