2a-5=3(a+1)+12a+7

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Solution for 2a-5=3(a+1)+12a+7 equation: 



2a-5=3(a+1)+12a+7

We move all terms to the left:

2a-5-(3(a+1)+12a+7)=0



We calculate terms in parentheses: -(3(a+1)+12a+7), so:

3(a+1)+12a+7

We add all the numbers together, and all the variables

12a+3(a+1)+7

We multiply parentheses

12a+3a+3+7

We add all the numbers together, and all the variables

15a+10

Back to the equation:

-(15a+10)



We get rid of parentheses

2a-15a-10-5=0

We add all the numbers together, and all the variables

-13a-15=0

We move all terms containing a to the left, all other terms to the right

-13a=15

a=15/-13

a=-1+2/13

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