2a/6a-8=4a+62a=

Solution for 2a/6a-8=4a+62a= equation:

2a/6a-8=4a+62a=

We move all terms to the left:

2a/6a-8-(4a+62a)=0


Domain of the equation: 6a!=0

a!=0/6

a!=0

a∈R


We add all the numbers together, and all the variables

2a/6a-(+66a)-8=0

We get rid of parentheses

2a/6a-66a-8=0

We multiply all the terms by the denominator


2a-66a*6a-8*6a=0

Wy multiply elements

-396a^2+2a-48a=0

We add all the numbers together, and all the variables

-396a^2-46a=0

a = -396; b = -46; c = 0;
Δ = b2-4ac
Δ = -462-4·(-396)·0
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-46}{2*-396}=\frac{0}{-792}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+46}{2*-396}=\frac{92}{-792}
=-23/198
$