2a2+11a+3=2a

Solution for 2a2+11a+3=2a equation:

2a^2+11a+3=2a

We move all terms to the left:

2a^2+11a+3-(2a)=0

We add all the numbers together, and all the variables

2a^2+9a+3=0

a = 2; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·2·3
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{57}}{2*2}=\frac{-9-\sqrt{57}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{57}}{2*2}=\frac{-9+\sqrt{57}}{4}
$