2a=(a/10)+44

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Solution for 2a=(a/10)+44 equation:



2a=(a/10)+44
We move all terms to the left:
2a-((a/10)+44)=0
We add all the numbers together, and all the variables
2a-((+a/10)+44)=0
We multiply all the terms by the denominator
2a*10)+44)-((+a=0
We add all the numbers together, and all the variables
a+2a*10)+44)-((=0
Wy multiply elements
20a^2+a=0
a = 20; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·20·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*20}=\frac{-2}{40} =-1/20 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*20}=\frac{0}{40} =0 $

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